8y^2=2

Solution for 8y^2=2 equation:

8y^2=2

We move all terms to the left:

8y^2-(2)=0

a = 8; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·8·(-2)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*8}=\frac{-8}{16}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*8}=\frac{8}{16}
=1/2
$